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| version 1.31, 2002/03/10 13:43:02 | version 1.32, 2002/03/11 14:17:15 |
|---|---|
| Line 1540 void evsij(char fileres[], double ***eij | Line 1540 void evsij(char fileres[], double ***eij |
| k=1; /* For example stepm=6 months */ | k=1; /* For example stepm=6 months */ |
| hstepm=k*YEARM; /* (a) Every k years of age (in months), for example every k=2 years 24 m */ | hstepm=k*YEARM; /* (a) Every k years of age (in months), for example every k=2 years 24 m */ |
| hstepm=1; /* or (b) We decided to compute the life expectancy with the smallest unit */ | hstepm=stepm; /* or (b) We decided to compute the life expectancy with the smallest unit */ |
| /* hstepm beeing the number of stepms, if hstepm=1 the length of hstepm is stepm. | /* hstepm beeing the number of stepms, if hstepm=1 the length of hstepm is stepm. |
| nhstepm is the number of hstepm from age to agelim | nhstepm is the number of hstepm from age to agelim |
| nstepm is the number of stepm from age to agelin. | nstepm is the number of stepm from age to agelin. |
| Look at hpijx to understand the reason of that which relies in memory size | Look at hpijx to understand the reason of that which relies in memory size |
| and note for a fixed period like k years */ | and note for a fixed period like k years */ |
| /* We decided (b) to get a life expectancy respecting the most precise curvature of the | /* We decided (b) to get a life expectancy respecting the most precise curvature of the |
| survival function given par stepm (the optimization length). Unfortunately it | survival function given by stepm (the optimization length). Unfortunately it |
| means that if the survival funtion is printed only each two years of age and if | means that if the survival funtion is printed only each two years of age and if |
| you sum them up and add 1 year (area under the trapezoids) you won't get the same | you sum them up and add 1 year (area under the trapezoids) you won't get the same |
| results. So we changed our mind and took the option of the best precision. | results. So we changed our mind and took the option of the best precision. |
| Line 1565 void evsij(char fileres[], double ***eij | Line 1565 void evsij(char fileres[], double ***eij |
| /* Computed by stepm unit matrices, product of hstepm matrices, stored | /* Computed by stepm unit matrices, product of hstepm matrices, stored |
| in an array of nhstepm length: nhstepm=10, hstepm=4, stepm=6 months */ | in an array of nhstepm length: nhstepm=10, hstepm=4, stepm=6 months */ |
| hpxij(p3mat,nhstepm,age,hstepm,x,nlstate,stepm,oldm, savm, ij); | hpxij(p3mat,nhstepm,age,hstepm,x,nlstate,stepm,oldm, savm, ij); |
| hf=hstepm/YEARM; /* Duration of hstepm expressed in year unit. */ | hf=hstepm*stepm/YEARM; /* Duration of hstepm expressed in year unit. */ |
| for(i=1; i<=nlstate;i++) | for(i=1; i<=nlstate;i++) |
| for(j=1; j<=nlstate;j++) | for(j=1; j<=nlstate;j++) |
| for (h=0, eij[i][j][(int)age]=0; h<=nhstepm-1; h++){ | for (h=0, eij[i][j][(int)age]=0; h<=nhstepm-1; h++){ |
| Line 1903 void printinghtml(char fileres[], char t | Line 1903 void printinghtml(char fileres[], char t |
| printf("Problem with %s \n",optionfilehtm), exit(0); | printf("Problem with %s \n",optionfilehtm), exit(0); |
| } | } |
| fprintf(fichtm,"<body><ul> <font size=\"6\">Imach, Version 0.71a </font> <hr size=\"2\" color=\"#EC5E5E\"> | fprintf(fichtm,"<body><ul> <font size=\"6\">Imach, Version 0.71c </font> <hr size=\"2\" color=\"#EC5E5E\"> |
| Title=%s <br>Datafile=%s Firstpass=%d Lastpass=%d Stepm=%d Weight=%d Model=%s<br> | Title=%s <br>Datafile=%s Firstpass=%d Lastpass=%d Stepm=%d Weight=%d Model=%s<br> |
| Total number of observations=%d <br> | Total number of observations=%d <br> |
| Line 2466 int main(int argc, char *argv[]) | Line 2466 int main(int argc, char *argv[]) |
| double dateprev1, dateprev2,jproj1,mproj1,anproj1,jproj2,mproj2,anproj2; | double dateprev1, dateprev2,jproj1,mproj1,anproj1,jproj2,mproj2,anproj2; |
| char version[80]="Imach version 0.71a, March 2002, INED-EUROREVES "; | char version[80]="Imach version 0.71c, March 2002, INED-EUROREVES "; |
| char *alph[]={"a","a","b","c","d","e"}, str[4]; | char *alph[]={"a","a","b","c","d","e"}, str[4]; |
| Line 3175 while((c=getc(ficpar))=='#' && c!= EOF){ | Line 3175 while((c=getc(ficpar))=='#' && c!= EOF){ |
| /*---------- Forecasting ------------------*/ | /*---------- Forecasting ------------------*/ |
| if((stepm == 1) && (model==".")){ | if((stepm == 1) && (strcmp(model,".")==0)){ |
| prevforecast(fileres, anproj1,mproj1,jproj1, agemin,agemax, dateprev1, dateprev2,mobilav, agedeb, fage, popforecast, popfile, anproj2,p, i1); | prevforecast(fileres, anproj1,mproj1,jproj1, agemin,agemax, dateprev1, dateprev2,mobilav, agedeb, fage, popforecast, popfile, anproj2,p, i1); |
| if (popforecast==1) populforecast(fileres, anpyram,mpyram,jpyram, agemin,agemax, dateprev1, dateprev2,mobilav, agedeb, fage, popforecast, popfile, anpyram1,p, i1); | if (popforecast==1) populforecast(fileres, anpyram,mpyram,jpyram, agemin,agemax, dateprev1, dateprev2,mobilav, agedeb, fage, popforecast, popfile, anpyram1,p, i1); |
| free_matrix(mint,1,maxwav,1,n); | free_matrix(mint,1,maxwav,1,n); |
| free_matrix(anint,1,maxwav,1,n); free_imatrix(s,1,maxwav+1,1,n); | free_matrix(anint,1,maxwav,1,n); free_imatrix(s,1,maxwav+1,1,n); |
| free_vector(weight,1,n);} | free_vector(weight,1,n);} |
| else{ | else{ |
| erreur=108; | erreur=108; |
| printf("Error %d!! You can only forecast the prevalences if the optimization\n has been performed with stepm = 1 (month) instead of %d\n", erreur, stepm); | printf("Warning %d!! You can only forecast the prevalences if the optimization\n has been performed with stepm = 1 (month) instead of %d or model=. instead of '%s'\n", erreur, stepm, model); |
| } | } |