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version 1.326, 2022/07/26 17:33:55	version 1.327, 2022/07/27 14:47:35
Line 1	Line 1
/* $Id$	/* $Id$
$State$	$State$
$Log$	$Log$
	Revision 1.327 2022/07/27 14:47:35 brouard
	Summary: Still a problem for one-step probabilities in case of quantitative variables

Revision 1.326 2022/07/26 17:33:55 brouard	Revision 1.326 2022/07/26 17:33:55 brouard
Summary: some test with nres=1	Summary: some test with nres=1

Line 6968 To be simple, these graphs help to under	Line 6971 To be simple, these graphs help to under
cov[2+nagesqr+Tage[k]]=nbcode[Tvar[Tage[k]]][codtabm(j1,k)]*cov[2];	cov[2+nagesqr+Tage[k]]=nbcode[Tvar[Tage[k]]][codtabm(j1,k)]*cov[2];
/* cov[++k1]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]cov[2]; /	/* cov[++k1]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]cov[2]; /
} else if(Dummy[Tage[k]]==3){ /* quantitative with age */	} else if(Dummy[Tage[k]]==3){ /* quantitative with age */
cov[2+nagesqr+Tage[k]]=Tqresult[nres][k];	printf("Internal IMaCh error, don't know which value for quantitative covariate with age, Tage[k]%d, k=%d, Tvar[Tage[k]]=V%d, age=%d\n",Tage[k],k ,Tvar[Tage[k]], (int)cov[2]);
	exit(1);
	/* cov[2+nagesqr+Tage[k]]=meanq[k]/idq[k]cov[2];/\ Using the mean of quantitative variable Tvar[Tage[k]] /\* Tqresult[nres][k]; \/ /
/* cov[++k1]=Tqresult[nres][k]; */	/* cov[++k1]=Tqresult[nres][k]; */
}	}
/* cov[2+Tage[k]+nagesqr]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]cov[2]; /	/* cov[2+Tage[k]+nagesqr]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]cov[2]; /