Log filename:biaspar.log Imach version 0.98q2, April 2015,INED-EUROREVES-Institut de longevite-Japan Society for the Promotion of Science (Grant-in-Aid for Scientific Research 25293121), Intel Software 2015 $Revision: 1.4 $ $Date: 2015/08/04 07:15:48 $ Enter the parameter file name: pathimach=Z:\imachcvs\NetBeans\imach\src\ pathtot=Z:\imachcvs\NetBeans\imach\html\doc\biaspar.imach path=Z:\imachcvs\NetBeans\imach\html\doc\ optionfile=biaspar.imach optionfilext=imach optionfilefiname='biaspar' Compiled with: Intel ICC/ICPC Microsoft Visual Studio for Windows (x64 and x86) 32-bitThe programm is not running under WOW64 (i.e probably on a 64bit Windows). Local time (at start): Tue May 05 11:13:23 2015 # Imach version 0.98q2, April 2015, INED-EUROREVES title=1st_example datafile=data1.txt lastobs=8600 firstpass=1 lastpass=4 ftol=1.000000e-008 stepm=1 ncovcol=2 nlstate=2 ndeath=1 maxwav=4 mle=1 weight=0 model=1+age+. # Parameters 11 0.000000 0.000000 12 0.000000 0.000000 21 0.000000 0.000000 22 0.000000 0.000000 # Scales 12 0.000000e+000 0.000000e+000 13 0.000000e+000 0.000000e+000 21 0.000000e+000 0.000000e+000 23 0.000000e+000 0.000000e+000 #covariance matrix# 121 0.00000e+000 122 0.00000e+000 0.00000e+000 131 0.00000e+000 0.00000e+000 0.00000e+000 132 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 211 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 212 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 231 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 232 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 0.00000e+000 Total number of individuals= 8270, Agemin = 70.00, Agemax= 104.17 Delay (in months) between two waves Min=1 (for indiviudal 6017) Max=74 (5168) Mean=24.040080 Age 70 1.=665 loss[1]=5.1% 2.=0 loss[2]=NaNQ% 1.=631 prev[1]=100.0% 2.=0 prev[2]=0.0% 1-1=34 11=563 12=33 13=35 33=6 Age 71 1.=663 loss[1]=5.7% 2.=2 loss[2]=0.0% 1.=625 prev[1]=99.7% 2.=2 prev[2]=0.3% 1-1=38 11=530 12=47 13=48 21=1 22=1 3-1=2 33=31 Age 72 1.=1181 loss[1]=5.6% 2.=35 loss[2]=5.7% 1.=1115 prev[1]=97.1% 2.=33 prev[2]=2.9% 1-1=66 11=969 12=70 13=76 2-1=2 21=9 22=18 23=6 3-1=2 33=87 Age 73 1.=1119 loss[1]=5.1% 2.=48 loss[2]=8.3% 1.=1062 prev[1]=96.0% 2.=44 prev[2]=4.0% 1-1=57 11=912 12=71 13=79 2-1=4 21=12 22=26 23=6 3-1=12 33=94 Age 74 1.=1563 loss[1]=4.2% 2.=90 loss[2]=4.4% 1.=1497 prev[1]=94.6% 2.=86 prev[2]=5.4% 1-1=66 11=1277 12=104 13=116 2-1=4 21=30 22=41 23=15 3-1=4 33=125 Age 75 1.=1463 loss[1]=6.2% 2.=98 loss[2]=7.1% 1.=1372 prev[1]=93.8% 2.=91 prev[2]=6.2% 1-1=91 11=1155 12=98 13=119 2-1=7 21=15 22=55 23=21 3-1=4 33=124 Age 76 1.=1390 loss[1]=4.5% 2.=112 loss[2]=3.6% 1.=1328 prev[1]=92.5% 2.=108 prev[2]=7.5% 1-1=62 11=1090 12=111 13=127 2-1=4 21=25 22=54 23=29 3-1=4 33=142 Age 77 1.=1271 loss[1]=5.0% 2.=101 loss[2]=5.9% 1.=1208 prev[1]=92.7% 2.=95 prev[2]=7.3% 1-1=63 11=962 12=131 13=115 2-1=6 21=24 22=52 23=19 3-1=7 33=145 Age 78 1.=1166 loss[1]=4.9% 2.=122 loss[2]=4.1% 1.=1109 prev[1]=90.5% 2.=117 prev[2]=9.5% 1-1=57 11=894 12=111 13=104 2-1=5 21=21 22=75 23=21 3-1=4 33=146 Age 79 1.=1045 loss[1]=5.7% 2.=133 loss[2]=5.3% 1.=985 prev[1]=88.7% 2.=126 prev[2]=11.3% 1-1=60 11=773 12=109 13=103 2-1=7 21=31 22=68 23=27 3-1=8 33=136 Age 80 1.=986 loss[1]=4.1% 2.=128 loss[2]=3.1% 1.=946 prev[1]=88.4% 2.=124 prev[2]=11.6% 1-1=40 11=718 12=140 13=88 2-1=4 21=21 22=71 23=32 3-1=6 33=121 Age 81 1.=872 loss[1]=4.9% 2.=130 loss[2]=3.8% 1.=829 prev[1]=86.9% 2.=125 prev[2]=13.1% 1-1=43 11=629 12=102 13=98 2-1=5 21=24 22=74 23=27 3-1=5 33=126 Age 82 1.=803 loss[1]=4.4% 2.=146 loss[2]=4.1% 1.=768 prev[1]=84.6% 2.=140 prev[2]=15.4% 1-1=35 11=546 12=131 13=91 2-1=6 21=15 22=77 23=48 3-1=11 33=100 Age 83 1.=726 loss[1]=6.5% 2.=116 loss[2]=0.9% 1.=679 prev[1]=85.5% 2.=115 prev[2]=14.5% 1-1=47 11=456 12=124 13=99 2-1=1 21=19 22=71 23=25 3-1=8 33=133 Age 84 1.=622 loss[1]=5.6% 2.=147 loss[2]=4.1% 1.=587 prev[1]=80.6% 2.=141 prev[2]=19.4% 1-1=35 11=394 12=112 13=81 2-1=6 21=18 22=82 23=41 3-1=5 33=114 Age 85 1.=526 loss[1]=4.4% 2.=127 loss[2]=6.3% 1.=503 prev[1]=80.9% 2.=119 prev[2]=19.1% 1-1=23 11=315 12=122 13=66 2-1=8 21=13 22=67 23=39 3-1=4 33=137 Age 86 1.=464 loss[1]=5.2% 2.=130 loss[2]=6.2% 1.=440 prev[1]=78.3% 2.=122 prev[2]=21.7% 1-1=24 11=271 12=103 13=66 2-1=8 21=18 22=70 23=34 3-1=3 33=112 Age 87 1.=372 loss[1]=4.8% 2.=143 loss[2]=2.8% 1.=354 prev[1]=71.8% 2.=139 prev[2]=28.2% 1-1=18 11=219 12=79 13=56 2-1=4 21=15 22=71 23=53 3-1=1 33=81 Age 88 1.=283 loss[1]=3.9% 2.=164 loss[2]=6.7% 1.=272 prev[1]=64.0% 2.=153 prev[2]=36.0% 1-1=11 11=172 12=63 13=37 2-1=11 21=25 22=84 23=44 3-1=8 33=102 Age 89 1.=227 loss[1]=3.5% 2.=152 loss[2]=4.6% 1.=219 prev[1]=60.2% 2.=145 prev[2]=39.8% 1-1=8 11=135 12=45 13=39 2-1=7 21=21 22=73 23=51 3-1=2 33=77 Age 90 1.=181 loss[1]=3.9% 2.=143 loss[2]=4.9% 1.=174 prev[1]=56.1% 2.=136 prev[2]=43.9% 1-1=7 11=104 12=41 13=29 2-1=7 21=18 22=82 23=36 3-1=1 33=75 Age 91 1.=146 loss[1]=4.1% 2.=109 loss[2]=8.3% 1.=140 prev[1]=58.3% 2.=100 prev[2]=41.7% 1-1=6 11=78 12=36 13=26 2-1=9 21=11 22=51 23=38 3-1=3 33=77 Age 92 1.=114 loss[1]=6.1% 2.=101 loss[2]=2.0% 1.=107 prev[1]=51.9% 2.=99 prev[2]=48.1% 1-1=7 11=47 12=43 13=17 2-1=2 21=11 22=52 23=36 3-1=2 33=61 Age 93 1.=78 loss[1]=3.8% 2.=89 loss[2]=12.4% 1.=75 prev[1]=49.0% 2.=78 prev[2]=51.0% 1-1=3 11=36 12=25 13=14 2-1=11 21=10 22=46 23=22 3-1=2 33=62 Age 94 1.=51 loss[1]=3.9% 2.=71 loss[2]=1.4% 1.=49 prev[1]=41.2% 2.=70 prev[2]=58.8% 1-1=2 11=24 12=8 13=17 2-1=1 21=4 22=39 23=27 3-1=1 33=37 Age 95 1.=38 loss[1]=5.3% 2.=57 loss[2]=5.3% 1.=36 prev[1]=40.0% 2.=54 prev[2]=60.0% 1-1=2 11=16 12=13 13=7 2-1=3 21=4 22=31 23=19 3-1=1 33=39 Age 96 1.=25 loss[1]=4.0% 2.=43 loss[2]=4.7% 1.=24 prev[1]=36.9% 2.=41 prev[2]=63.1% 1-1=1 11=11 12=9 13=4 2-1=2 21=2 22=22 23=17 3-1=2 33=25 Age 97 1.=11 loss[1]=0.0% 2.=36 loss[2]=8.3% 1.=11 prev[1]=25.0% 2.=33 prev[2]=75.0% 11=4 12=7 2-1=3 21=2 22=22 23=9 33=23 Age 98 1.=5 loss[1]=0.0% 2.=21 loss[2]=0.0% 1.=5 prev[1]=19.2% 2.=21 prev[2]=80.8% 11=1 12=4 21=1 22=13 23=7 3-1=1 33=17 Age 99 1.=6 loss[1]=0.0% 2.=14 loss[2]=0.0% 1.=6 prev[1]=30.0% 2.=14 prev[2]=70.0% 11=3 12=1 13=2 21=2 22=2 23=10 33=6 Age 100 1.=2 loss[1]=0.0% 2.=9 loss[2]=0.0% 1.=2 prev[1]=18.2% 2.=9 prev[2]=81.8% 11=1 12=1 21=2 22=5 23=2 33=2 Age 101 1.=2 loss[1]=50.0% 2.=0 loss[2]=NaNQ% 1.=1 prev[1]=100.0% 2.=0 prev[2]=0.0% 1-1=1 12=1 3-1=1 33=3 Age 102 1.=2 loss[1]=0.0% 2.=1 loss[2]=0.0% 1.=2 prev[1]=66.7% 2.=1 prev[2]=33.3% 12=2 22=1 33=1 Age 103 1.=0 loss[1]=NaNQ% 2.=0 loss[2]=NaNQ% 1.=0 prev[1]=NaNQ% 2.=0 prev[2]=NaNQ% Age 104 1.=0 loss[1]=NaNQ% 2.=0 loss[2]=NaNQ% 1.=0 prev[1]=NaNQ% 2.=0 prev[2]=NaNQ% Age 105 1.=0 loss[1]=NaNQ% 2.=0 loss[2]=NaNQ% 1.=0 prev[1]=NaNQ% 2.=0 prev[2]=NaNQ% Age 106 1.=0 loss[1]=NaNQ% 2.=0 loss[2]=NaNQ% 1.=0 prev[1]=NaNQ% 2.=0 prev[2]=NaNQ% -1-1=69 -11=718 -12=195 -13=261 Total 1.=18068 loss[1]=5.0% 2.=2818 loss[2]=4.9% 1.=17161 prev[1]=86.5% 2.=2681 prev[2]=13.5% -1-1=69 -11=718 -12=195 -13=261 1-1=907 11=13305 12=2097 13=1759 2-1=137 21=424 22=1496 23=761 3-1=114 33=2567 Powell Powell iter=1 -2*LL=429817.002238171520 0 sec. 0 sec. 1 0.000000000000 2 0.000000000000 3 0.000000000000 4 0.000000000000 5 0.000000000000 6 0.000000000000 7 0.000000000000 8 0.000000000000 Considering the time needed for this last iteration #1: 0 seconds, - if your program needs 10 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 0 minute(s) 0 second(s) i.e. on Tue May 05 11:13:34 2015 (current time is Tue May 05 11:13:34 2015); - if your program needs 20 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 0 minute(s) 0 second(s) i.e. on Tue May 05 11:13:34 2015 (current time is Tue May 05 11:13:34 2015); - if your program needs 30 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 0 minute(s) 0 second(s) i.e. on Tue May 05 11:13:34 2015 (current time is Tue May 05 11:13:34 2015); 1.....2................3..........4.....................5.....6............7........8..............................Gaining to use new average direction of P0 P8 instead of biggest increase direction 5 : Powell iter=2 -2*LL=61164.969498491329 14 sec. 0 sec. 1 10.361177425153 2 -0.000405752275 3 -0.426051135866 4 0.000411058449 5 3.199377281172 6 -0.000133628129 7 -0.817385555710 8 0.000414645460 Considering the time needed for this last iteration #2: 14 seconds, - if your program needs 10 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 1 minute(s) 52 second(s) i.e. on Tue May 05 11:15:40 2015 (current time is Tue May 05 11:13:48 2015); - if your program needs 20 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 4 minute(s) 12 second(s) i.e. on Tue May 05 11:18:00 2015 (current time is Tue May 05 11:13:48 2015); - if your program needs 30 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 6 minute(s) 32 second(s) i.e. on Tue May 05 11:20:20 2015 (current time is Tue May 05 11:13:48 2015); 1............2....................3......4..................5..................6.................7..........8........ Powell iter=3 -2*LL=58792.325287399166 43 sec. 0 sec. 1 5.025320473019 2 -0.001271522649 3 -2.292075301862 4 0.005675436950 5 3.064920310602 6 -0.003614340923 7 -1.082612744376 8 -0.006929410302 Considering the time needed for this last iteration #3: 43 seconds, - if your program needs 10 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 5 minute(s) 1 second(s) i.e. on Tue May 05 11:19:32 2015 (current time is Tue May 05 11:14:31 2015); - if your program needs 20 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 12 minute(s) 11 second(s) i.e. on Tue May 05 11:26:42 2015 (current time is Tue May 05 11:14:31 2015); - if your program needs 30 iterations to converge, convergence will be reached in 0 day(s) 0 hour(s) 19 minute(s) 21 second(s) i.e. on Tue May 05 11:33:52 2015 (current time is Tue May 05 11:14:31 2015); 1.........2....................3.........4....................5..................6.................7...........8...............Gaining to use new average direction of P0 P8 instead of biggest increase direction 1 : Powell iter=4 -2*LL=51671.511989744839 13 sec. 0 sec. 1 -0.738171836654 2 -0.005095967053 3 -6.249885480035 4 0.018850231372 5 2.760427678775 6 0.002137535586 7 -0.810125973911 8 -0.019962106000 1........2................3..........4..................5.................6................7.................8.......... Powell iter=5 -2*LL=51564.973406501369 13 sec. 0 sec. 1 -0.640102693049 2 -0.004671488059 3 -6.355728607893 4 0.019354535332 5 2.794272826941 6 2.309115769305 7 1.799068527323 8 -4.254984576420 1........2.............3.........4..................5.................6.................7.................8.......... Powell iter=6 -2*LL=51512.620168158559 12 sec. 0 sec. 1 -0.707671793492 2 -0.004043840434 3 -6.235710935103 4 0.019694131082 5 2.772348672077 6 4.883902697129 7 4.421901023083 8 -1.637606955042 1........2.............3...................4..................5.................6...............7.................8.......... Powell iter=7 -2*LL=51497.973086223668 13 sec. 0 sec. 1 -0.748745600049 2 -0.003548201851 3 -6.280610560550 4 0.020192016944 5 2.776035786301 6 6.512481518851 7 7.040490669592 8 0.979620465528 1........2.............3..........4..................5.................6..................7.................8........................Gaining to use new average direction of P0 P8 instead of biggest increase direction 8 : Powell iter=8 -2*LL=51469.726224868631 15 sec. 0 sec. 1 -0.833574313562 2 -0.002535454468 3 -6.362935045791 4 0.021191220259 5 2.782030172908 6 6.608886952762 7 12.367555241042 8 6.303685589096 1........2.............3..........4..................5.......6....................7..................8............... Powell iter=9 -2*LL=51460.597638570471 14 sec. 0 sec. 1 -0.819597388038 2 -0.001927771721 3 -6.366922190899 4 0.021608735010 5 2.788633894031 6 6.715764216787 7 11.126986364695 8 6.426838468958 1........2.............3.........4..................5..........6.........7.....................8..................................Gaining to use new average direction of P0 P8 instead of biggest increase direction 2 : Powell iter=10 -2*LL=51437.479784084469 17 sec. 0 sec. 1 -0.893774665883 2 -0.000533885740 3 -6.429458703340 4 0.022581850422 5 2.770188936631 6 6.798189075056 7 12.797974488056 8 6.485900015773 1................2..............3.........4..................5..............6...................7..................8.............................. Powell iter=11 -2*LL=51420.437001909391 42 sec. 0 sec. 1 -0.950697588560 2 -0.000527484177 3 -6.481470925397 4 0.022923641821 5 2.752623141516 6 6.798366227492 7 11.189519918460 8 6.148112871371 1...................2.......................